如何使用类构造函数为类实例定义接口

Question

I am building a application and part of the code allows developer to specify which component they want to render a certain part. I want users to know they need to implement an interface but I am not sure how to write typing correctly.

export interface ICustomComponent {
    templateObject: any;
}

export class MyComponent implements ICustomComponent {
}

export class MyLib {
    constructor(
        private yourComponent: ICustomComponent
    ) {}
}

new MyLib(MyComponent); <== Fails

I am writing code with Angular, and I cannot run new operator but let Angular to resolve and construct that component.

Here an example that illustrates my problem.

How to deal with this problem?

Answer 1

Since MyLib expects a class constructor, not class instance, you need to define an interface for a class constructor and specify that it returns the instance with the ICustomComponent interface:

interface ICustomComponent {
  templateObject: any;
}

interface ICustomComponentConstructor {
  new (...deps: any[]): ICustomComponent;
}

And then you can use it like this:

export class MyComponent implements ICustomComponent {
  templateObject: any;
}

export class MyLib {
  constructor(private yourComponent: ICustomComponentConstructor) {
  }
}

new MyLib(MyComponent);

You can read about interface for class constructors and instances here .