如何在Python中将列的第一个元素与CSV文件中的其他元素进行比较？

Question

I want to compare first element of a column with other elements of same column and next column and print element which is present once only in both the columns as well as value in its corresponding column. For eg:

Col1 Col2
111 243
111 145
213 111
289 200
222 213

In this example 243 is present only once but 111(value in corresponding column) is present more then once. I want to print only

289 200

My code is:

import csv
from collections import Counter, OrderedDict
class OrderedCounter(Counter, OrderedDict):
    pass
f = open("1.csv", 'r')
reader = csv.reader(f)
a = []
b = []
c = []
for row in reader:
    a.append(row[0])
    b.append(row[1])
val = [i for i,j in OrderedCounter(a).items() if j==1]
val1 = [i for i,j in OrderedCounter(b).items() if j==1]

It is giving me the unique values of each column

Answer 1

from collections import Counter    
import csv

values = Counter()
data = {}

with open('1.csv') as f_input:
    csv_input = csv.reader(f_input)
    header = next(csv_input)    # comment out if no actual header

    for row in csv_input:
        values[row[0]] += 1
        values[row[1]] += 1
        data[row[0]] = row[1]

for value, count in values.items():
    try:
        if count == 1 and values[data[value]] == 1:
            print '{} {}'.format(value, data[value])
    except KeyError as e:
        pass

This would display:

289  200