温莎城堡注册开放式通用ILogger

Question

I have Simple Injector registration of my:

container.RegisterConditional(typeof(ILogManager),
c => typeof(LogManager<>).MakeGenericType(c.Consumer.ImplementationType),
Lifestyle.Singleton,
c => true);

I need to register same LogManager in different project using Castle Windsor.

I have tried

container.Register(Component.For(typeof(ILogger))
            .ImplementedBy(typeof(Log4NetLogger<>).MakeGenericType())
            .LifeStyle.Singleton.Start());

Cannot make it working.

Answer 1

Unfortunately this is more complicated with Castle. But you can achieve the same result with SubDependencyResolver:

public class LoggerResolver : ISubDependencyResolver
{
    public bool CanResolve(CreationContext context, ISubDependencyResolver contextHandlerResolver, ComponentModel model, DependencyModel dependency)
    {
        return dependency.TargetType == typeof(ILogger);
    }

    public object Resolve(CreationContext context, ISubDependencyResolver contextHandlerResolver, ComponentModel model, DependencyModel dependency)
    {
        var logger = typeof(LogManager<>).MakeGenericType(model.Implementation);
        return Activator.CreateInstance(logger);
    }
}

than add it into the kernel:

Kernel.Resolver.AddSubResolver(new LoggerResolver())

Another way is to use GenericImplementationMatchingStrategy. This one will work also in situation if LogManager has some dependencies:

public class OpenGenericAncestorMatchingStrategy : IGenericImplementationMatchingStrategy
{
    public Type[] GetGenericArguments(ComponentModel model, CreationContext context)
    {
        return new[] { context.Handler.ComponentModel.Implementation };
    }
}

and registration:

container.Register(Component.For<ILogger>().ImplementedBy(typeof(LogManager<>), new OpenGenericAncestorMatchingStrategy()));