如何安排在Windows引导后立即执行的Powershell脚本？

Question

I want to run a script starting some application on Windows when the machine is started/restarted.

I tried the Register-ScheduledJob cmdlet :

Register-ScheduledJob -Name "MyJob" -ScriptBlock {.\C:\Users\Administrator\my_script.ps1 -input_value xyz} -Trigger (New-JobTrigger -AtStartup)

However, nothing gets executed at the startup and the output folder on

$home\AppData\Local\Microsoft\Windows\PowerShell\ScheduledJobs directory

The Task Scheduler tool does not show anything as well.

my_script.ps1 simply starts a Java jar as follows:

param(
[parameter(Mandatory=$TRUE,Position=0)]
  [string] $input_value
)


write-output "Starting my Java app ... "

start powershell {java -jar slave.jar <<-some params ...>> ; Read-Host}
Exit 0

Even if I try to run the job with Start-Job -DefinitionName MyJob , nothing happens although it outputs that its running ...

Any ideas?

Answer 1

The only way I know is if you run it in task scheduler .

schtasks /Create [/S <system> [/U <username> [/P [<password>]]]]
    [/RU <username> [/RP <password>]] /SC <schedule> [/MO <modifier>] [/D <day>]
    [/M <months>] [/I <idletime>] /TN <taskname> /TR <taskrun> [/ST <starttime>]
    [/RI <interval>] [ {/ET <endtime> | /DU <duration>} [/K] [/XML <xmlfile>] [/V1]]
    [/SD <startdate>] [/ED <enddate>] [/IT] [/Z] [/F]

Answer 2

I would create a Task in Task Scheduler and set the Trigger as "When a specific event is logged"

Then, set Log: to System and Source: to Kernal-General and Event ID: to 12 (or any event you would like to trigger the script on). 12 seems to always fire after a boot.

Under Action select Start a Program and set Program/script to PowerShell . In Add arguments (optional): enter -file "C:\\YourDirectory\\YourScript.ps1" .