使用Perl将字符串替换为具有特殊字符的变量

Question

I have a file with below content:

$ cat file
my name is PARESH.

Need to replace PARESH with content of variable `$REPLACE_WORD" using Perl.

perl -pi -e "s/PARESH/$REPLACE_WORD/g"  file

Problem is variable $REPLACE_WORD has special characters in it.

$REPLACE_WORD="c@sc9ey"

Answer 1

Perl interpolates scalars ( $foo ) and arrays ( @bar ) in double quotes "" . If you use single quotes '' instead, no interpolation happens.

$REPLACE_WORDS = 'c@sc9ey';

Note that hash variabels ( %baz ) are not interpolated.

Answer 2

使用双引号时，请使用\\转义特殊字符\\

$REPLACE_WORD = "c\@sc9ey";