[英]Is static initialization guaranteed here?
Yes, the Standard says f
will be constant initialized: 是的,标准说f
将不断初始化:
[basic.start.init]/2: [basic.start.init] / 2:
A constant initializer for an object
o
is an expression that is a constant expression, except that it may also invokeconstexpr
constructors foro
and its subobjects even if those objects are of non-literal class types [ Note: such a class may have a non-trivial destructor -- end note ]. 对象o
常量初始化器是一个表达式,它是一个常量表达式,除了它也可以为o
及其子对象调用constexpr
构造函数,即使这些对象是非文字类类型[ 注意:这样的类可能有非-trivial destructor - end note ]。 Constant initialization is performed: 执行常量初始化 :
... [a case for references] ...... [参考案例]
if an object with static or thread storage duration is initialized by a constructor call, and if the initialization full-expression is a constant initializer for the object; 如果具有静态或线程存储持续时间的对象由构造函数调用初始化,并且初始化full-expression是对象的常量初始值设定项;
... [a case for objects initialized without a constructor call] ... [没有构造函数调用初始化对象的情况]
Together, zero-initialization and constant initialization are called static initialization ; 零初始化和常量初始化一起称为静态初始化 ; all other initialization is dynamic initialization . 所有其他初始化是动态初始化 。 Static initialization shall be performed before any dynamic initialization takes place. 在进行任何动态初始化之前,应执行静态初始化。
The initialization full-expression is simply the call of Foo
's default constructor, which is a constant expression. 初始化full-expression只是调用Foo
的默认构造函数,它是一个常量表达式。
MSVC is wrong to emit code to initialize f
. MSVC发出代码来初始化f
是错误的。
Standard-wise, yes. 标准方面,是的。 Reality-wise, no. 现实,没有。
You are at the mercy of compiler venders when it comes to static initialization compliance. 在静态初始化合规性方面,您受编译器供应商的支配。
[edit] Clang is a special compiler — from the beginning its creators have been interested in full standards compliance. [编辑] Clang是一个特殊的编译器 - 从一开始它的创建者一直对完全符合标准感兴趣。
如果你要将f本身声明为constexpr Foo f,我相信它也会在msvc中(至少对2015年);
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