简体   繁体   English

使用Xcode 9和AES解密的CryptoSwift

[英]CryptoSwift with Xcode 9 and AES Decryption

I am using Xcode 9.0 and CryptoSwift (0.7.2). 我正在使用Xcode 9.0和CryptoSwift(0.7.2)。 I am trying to extend String to decrypt an AES128 encrypted string. 我正在尝试扩展String以解密AES128加密字符串。 I've added CryptoSwift successfully with Pods but I get the following compilation error - what am I doing wrong? 我已经使用Pod成功添加了CryptoSwift,但是我收到了以下编译错误 - 我做错了什么?

'PKCS7' cannot be constructed because it has no accessible initializers 无法构造'PKCS7',因为它没有可访问的初始值设定项

在此输入图像描述

Here is the extension: 这是扩展名:

import Foundation
import CryptoSwift

extension String {

    // https://stackoverflow.com/questions/27072021/aes-encrypt-and-decrypt
    func aesDecrypt(key: String, iv: String) throws -> String {
        let data = Data(base64Encoded: self)!
        let decrypted = try! AES(key: key, iv: iv, blockMode: .CBC, padding: PKCS7()).decrypt([UInt8](data))
        let decryptedData = Data(decrypted)
        return String(bytes: decryptedData.bytes, encoding: .utf8) ?? "Could not decrypt"
    }

}

I've checked out CryptoSwift 's documentation, and I found a sample code: 我查看了CryptoSwift的文档,我找到了一个示例代码:

let decrypted = try AES(key: key, iv: iv, blockMode: .CBC, padding: .pkcs7).decrypt(encrypted)

and I think it uses .pkcs7 , instead of PKCS7() . 我认为它使用.pkcs7而不是PKCS7()

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM