如何从包含键作为字典列表的字典中获取第一个键值对（即“类型”：45）
[英]How do i fetch first key value pair (i.e., 'type': 45) from a dictionary which contains key as list with dictionaries
问题描述
{'alarms': [{'date': '20170925T235525-0700',
'id': 8,
'ip': '172.26.70.4',
'severity': 4,
'type': 45},
{'date': '20170925T235525-0700',
'id': 7,
'ip': '172.26.70.4',
'severity': 4,
'type': 45},
{'date': '20170925T235525-0700',
'id': 6,
'ip': '172.26.70.4',
'severity': 4,
'type': 45},
{'date': '20170925T220858-0700',
'id': 5,
'ip': '172.26.70.4',
'severity': 6,
'type': 44},
{'date': '20170925T220857-0700',
'id': 4,
'ip': '172.26.70.4',
'severity': 6,
'type': 44},
{'date': '20170925T220857-0700',
'id': 3,
'ip': '172.26.70.4',
'severity': 6,
'type': 44},
{'date': '20170925T220856-0700',
'id': 2,
'severity': 6,
'type': 32},
{'date': '20170925T220850-0700', 'id': 1, 'severity': 6, 'type': 1},
{'date': '20170925T220850-0700',
'id': 0,
'severity': 6,
'type': 33}]}
Need to fetch first key value pair (ie, 'type': 45) 
需要获取第一个键值对（即“类型”：45）
Kindly guide, I am trying it on Python 2.7. 谨此指导，我正在Python 2.7上进行尝试。
3 个解决方案
解决方案1
0 2017-09-26 11:43:07
Your data is a dictionary where the `"alarms" key is associated with a list of dictionaries. 您的数据是一个字典，其中“ alarms”键与一个词典列表相关联。
That dictionary is in the list associated with the "alarms" key. 该词典在与"alarms"键关联的列表中。 So you can fetch it with: 因此，您可以通过以下方式获取它：
data['alarms'][0]
with data the variable that stores this structure. 与data存储该结构的变量。 So: 所以：
>>> data['alarms'][0]
{'date': '20170925T235525-0700', 'severity': 4, 'id': 8, 'ip': '172.26.70.4', 'type': 45}
解决方案2
0 2017-09-26 11:48:05
you will need to do : 您将需要执行以下操作：
def return_correct_dict(data):
for d in data['alarms']:
if d.get('type',"") == 45:
return d
解决方案3
0 2017-09-26 11:57:07
You have a dictionary of a list of dictionaries. 您有词典列表的字典。 Suppose your dictionary is stored in a variable named dict . 假设您的字典存储在名为dict的变量中。
dict['alarm'][0]['type'] will give you the value 45.
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