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如何从数组中获取非空数组

[英]How to fetch non-empty Array from an Array

The Array contains some non-empty arrays . 数组包含一些非空数组。 i need to fetch respective non-empty array and print the data . 我需要获取相应的非空数组并打印数据。 eg: array 2 has variable as importTroubles->troubleMessage how can i print that? 例如:数组2的变量为importTroubles-> troubleMessage我该如何打印?

Array
(
 [0] => stdClass Object
    (
    )

[1] => stdClass Object
    (
    )

[2] => stdClass Object
    (
        [return] => stdClass Object
            (
                [failureMessage] => 
                [importTroubles] => stdClass Object
                    (
                        [kind] => ParseError
                        [rowNumber] => 1
                        [troubleMessage] => Field "number1" has invalid value: "+16046799329". Invalid phone number //need to print this..
                    )

                [keyFields] => number1
                [uploadDuplicatesCount] => 0
                [uploadErrorsCount] => 1
                [warningsCount] => stdClass Object
                    (
                    )

                [callNowQueued] => 0
                [crmRecordsInserted] => 0
                [crmRecordsUpdated] => 2
                [listName] => new camp from CRM1-TargetList-CRM
                [listRecordsDeleted] => 0
                [listRecordsInserted] => 2
            )

    )

[3] => stdClass Object
    (
    )

[4] => stdClass Object
    (
    )

)

im trying with this method : 我正在尝试使用这种方法:

foreach($result as $object) {
foreach ($object as $items) {

    if($items !== '')
    {
        foreach ($items as $item) {
            echo "ERROR".$item->troubleMessage;
        }
    }

}
}

Thanks for your efforts 感谢您的努力

Make use of php function empty() 利用php函数empty()

Change your if condition as in below code : 更改您的if条件,如以下代码所示:

foreach($result as $object) {
 foreach ($object as $items) {
    if( !empty($items) )
    {
        foreach ($items as $item) {
          if( isset($item->troubleMessage) )
          {
            echo "ERROR".$item->troubleMessage;
          }
        }
    }
 }
}

Now it will echo only if $items has values. 现在,仅当$items具有值时,它才会回显。

将您的if($items !== '')更改为if(!empty($items))if($items)if($items[0])希望对您有所帮助

You don't have to iterate each object if you're only looking for a single specific item nested within it. 如果只需要查找嵌套在其中的单个特定项目,则不必迭代每个对象。 You can just refer to that item directly. 您可以直接直接引用该项目。

foreach ($your_array as $object) {
    if (isset($object->return->importTroubles->troubleMessage)) {
        echo $object->return->importTroubles->troubleMessage;
    }
}

If you check if that specific nested object variable is set, it will ignore any empty objects. 如果检查是否设置了特定的嵌套对象变量,它将忽略任何空对象。

You could use Collection 您可以使用Collection

use Illuminate\Support\Collection;

$collection = new Collection($result);

$items = $collection->filter(function($object) {

    return isset($object->return->importTroubles->troubleMessage);

})->map(function($object) {

    return $object->return->importTroubles->troubleMessage;

});

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