PHP MySQL获取日期并将每个月的数据拆分为JSON

Question

I have an MySQL -database with a table which contains a lot of events, eg concerts. The structure of the table is pretty simple:

id (int, 11, pk , ai)
event_name (varchar, 255)
event_location (varchar, 255)
event_date (date)

Now, for display purpose on the frontend, I would like to show the events in some kind of "month overview", like:

January
- event blabla  10/01/17
- event thisandthat  17/01/17

February
- event something 05/02/17
- event another something 13/02/17

...etc etc

So I was thinking about how to achieve this. Should I create another table and give any month an ID, and also add an "month_id" field in the events-table?

I would like to do some json_encode so that in the end I will have an JSON -array with objects which has all the data.

Any suggestions? Or even better: any examples?

** UPDATE **

My desired result should look something like this:

[{
    "January": [{
            "event_name": "blabla",
            "event_location" : "somewhere",
            "event_date": "2017-01-10" 
        },
        {
            "event_name": "blabla",
            "event_location" : "somewhere",
            "event_date": "2017-01-17"
        }
    ]
},
{
    "February": [{
            "event_name": "blabla",
            "event_location" : "somewhere",
            "event_date": "2017-02-10"
        },
        {
            "event_name": "blabla",
            "event_location" : "somewhere",
            "event_date": "2017-02-17"
        }
    ]
},
{
    "March": [{
            "event_name": "blabla",
            "event_location" : "somewhere",
            "event_date": "2017-03-10"
        },
        {
            "event_name": "blabla",
            "event_location" : "somewhere",
            "event_date": "2017-03-17"
        }
    ]
  }
]

Answer 1

$sql="SELECT MONTH(event_date) event_month, * FROM events ORDER BY event_date";

Then enter in a foreach loop with results comparing if event_month is null (first loop) or the same of the previous loop. If it is the same your into the month events subset otherwise you're starting a new month.

$currentmonth=null;
for($row in $rows){
    if($row["event_month"]!=$currentmonth){
        echo "Month ".$row["event_month"];
        $row["event_month"]=$currentmonth;      
    }
    echo "\tevent ".$row["event_name"];
}

Answer 2

You can go ahead and extract the month in your query, something like this

SELECT event_name, event_location, event_date,
       DATE_FORMAT(event_date, '%Y - %M') AS event_month
WHERE ...
ORDER BY event_date

Whatever format works for you. Including the year may or may not be useful, depending on what you're doing with it. If you don't need the year included, you can just use MONTH or MONTHNAME instead.

Then group by that as you fetch the rows from your query result.

<?php

while ($row = $stmt->yourFavoriteFetchMethod()) {
    $result[$row->event_month][] = $row;
}

echo json_encode($result);