[英]How to convert the tree structured json to Java object using gson
[
{
"sentence": "I want to buy shoes .",
"tree": {
"ROOT": [
{
"index": 2,
"token": "want",
"label": "VERB",
"pos": "VBP",
"tree": {
"nsubj": [
{
"index": 1,
"token": "I",
"label": "PRON",
"pos": "PRP"
}
],
"xcomp": [
{
"index": 4,
"token": "buy",
"label": "VERB",
"pos": "VB",
"tree": {
"aux": [
{
"index": 3,
"token": "to",
"label": "PRT",
"pos": "TO"
}
],
"dobj": [
{
"index": 5,
"token": "shoes",
"label": "NOUN",
"pos": "NNS"
}
]
}
}
],
"punct": [
{
"index": 6,
"token": ".",
"label": ".",
"pos": "."
}
]
}
}
]
}
}
]
This is tree represented in Json. 这是Json中表示的树。 But the keys for nested nodes keep changing.
但是嵌套节点的键不断变化。
For example "ROOT, nsubj, xcomp" ... etc. 例如“ ROOT,nsubj,xcomp”等。
How do I convert above json code to Java Object using gson. 如何使用gson将上述json代码转换为Java Object。
Above response is from syntaxnet Parsey_Mcparseface api I'm trying to use. 上面的响应来自我试图使用的syntaxnet Parsey_Mcparseface api。
Thanks in advance. 提前致谢。
Gson has a method Gson#fromJson
. Gson有方法
Gson#fromJson
。 For example, this is a code to read a simple String object. 例如,这是一个读取简单String对象的代码。
Gson gson = new Gson();
String str = gson.fromJson("\"hello\"", String.class);
System.out.println("String: " + str);
You need to prepare Java Object to read your proposed JSON. 您需要准备Java对象以读取建议的JSON。 But, you don't need to write code by yourself.
但是,您不需要自己编写代码。 There is a website providing automatical JSON object generator.
有一个网站提供自动JSON对象生成器。
jsonschema2pojo jsonschema2pojo
enter following items: 输入以下项目:
and enter your class name, for example "ParsedSentence" 然后输入您的班级名称,例如“ ParsedSentence”
then, write code. 然后,编写代码。 You will get object.
你会得到对象。
Gson gson = new Gson();
ParsedSentence parsed = gson.fromJson(longLongJsonString, ParsedSentence.class);
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