[英]How to add not null unique value to existing Django Model with default attribute
I need to add slug field to django model, and i thing it's better when it not null. 我需要向django模型添加slug字段,而且当它不为null时,它会更好。 So i'm trying to add slug to model
所以我试图将slug添加到模型中
slug = models.SlugField(
'URL',
unique=True,
default=id_generator,
)
my id_generator: 我的id_generator:
import string
import random
def id_generator():
size=16
chars=string.ascii_lowercase + string.digits
return ''.join(random.choice(chars) for x in range(size))
The problem is when i migrate changes. 问题是我迁移更改时。 Method id_generator is calling one time and uses the same value for all model objects.
方法id_generator正在调用一次,并对所有模型对象使用相同的值。 So i have dupliicate entrie in unique field.
所以我在独特的领域有重复的进步。 How can i generate unique values?
如何生成唯一值? Django 1.11.5
Django 1.11.5
PS I understand, that i can set null=True and customize model's save method to add slug when saving. PS我明白,我可以设置null = True并自定义模型的保存方法以在保存时添加slug。
MOST IMPORTANT: You have not good generator for unique slug, may be best way use uuid for example 最重要的是:你没有好的发电机用于独特的slug,可能是最好的方式使用uuid例如
import uuid
slug = models.CharField(max_length=64, blank=True, unique=True, default=uuid.uuid4)
by add-unique-fields 通过add-unique-fields
example first step migration, replace YOUMODEL: 示例第一步迁移,替换YOUMODEL:
from __future__ import unicode_literals
import string
import random
from django.db import migrations, models
def id_generator():
size=16
chars=string.ascii_lowercase + string.digits
return ''.join(random.choice(chars) for x in range(size))
def update_slug(pp, schema_editor):
for instance in YOUMODEL.objects.all():
# ^^^^^^^
instance.slug = id_generator()
instance.save()
class Migration(migrations.Migration):
operations = [
migrations.AddField(
model_name='YOUMODEL',
# ^^^^^^^
name='slug',
field=models.SlugField(null=True, verbose_name='URL'),
),
migrations.RunPython(code=update_slug)
]
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