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如何将参数传递给广播接收器类?

[英]How to pass parameters to Broadcast receiver class?

I have created a Broadcast receiver and it is working fine. 我创建了一个广播接收器,它工作正常。 but I need to pass a handler to that class. 但我需要将处理程序传递给该类。

 public static class DataReceiver extends BroadcastReceiver {

        Handler handler;

        DataReceiver(Handler loghandler) {
            this.handler = loghandler;
        }

          @Override
        public void onReceive(Context context, Intent intent) {
            //things goes here
        }
}

Currently I am using like this & It is working if constructor override is not available. 目前我正在使用这样的&如果构造函数重写不可用,它正在工作。

Intent intent = new Intent(this, DataReceiver .class);

but I need to pass the handler too. 但是我也需要通过处理程序。 How can I send the handler? 如何发送处理程序? Thanks 谢谢

I don't really understand what you are trying to accomplish but i think this may help you. 我不太了解您要完成的工作,但我认为这可能对您有所帮助。 You don't need to make a whole new class for your broadcast receiver but you can use it inside your Main Activity like this: 您不需要为广播接收器创建一个全新的类,但可以在“主要活动”中使用它,如下所示:

BroadcastReceiver receiveLocationReceiver = new BroadcastReceiver() {

        @Override
        public void onReceive(Context context, Intent intent) {
            // Your custom action
        }

    };

    IntentFilter receiveLocationFilter = new IntentFilter();
    receiveLocationFilter.addAction("android.intent.RECEIVE_LOCATION");

Register the receiver in "onStart": 在“ onStart”中注册接收器:

registerReceiver(receiveLocationReceiver, receiveLocationFilter);

Unregister it in "onStop": 在“ onStop”中注销:

unregisterReceiver(receiveLocationReceiver);

Then when you need to send the broadcast all you need is : 然后,当您需要发送广播时,您需要做的是:

Intent sendBroadcastIntent = new Intent("android.intent.RECEIVE_LOCATION");
sendBroadcast(sendBroadcastIntent);

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