[英]Sort by multiple columns MySQL
I have a table in which I have three fields with data type INT, INT and INT. 我有一个表,其中有三个字段,数据类型为INT,INT和INT。
I want to sort my select query using all these three columns. 我想使用所有这三列对我的选择查询进行排序。 Sort by ASC if field A <= 10, sort by DESC field2 and sort by ASC field 3. 如果字段A <= 10,则按ASC排序,按DESC字段2排序,按ASC字段3排序。
SELECT * FROM table1 WHERE id=uid
ORDER BY
CASE table1.field1
WHEN table1.field1 < 11 THEN table1.field1
END
ASC,
table1.field2 DESC,
table1.field3 ASC;
+------+--------+---------+
|field1| field2 | field3 |
+------+--------+---------+
| 1 | 4 | 1 |
+------+--------+---------+
| 2 | 3 | 2 |
+------+--------+---------+
| 9 | 2 | 4 |
+------+--------+---------+
| 10 | 1 | 7 |
+------+--------+---------+
For some reason the CASE
doesnt really work, if I exclude that it works but does sort all of field1 in ASC order while I only want the 10 first. 由于某种原因, CASE
真正起作用,如果我排除了它的作用,但确实按ASC顺序对所有field1进行了排序,而我只想先输入10。
There is no need for table1.field1
before WHEN
: 在WHEN
之前不需要table1.field1
:
SELECT *
FROM table1
WHERE id = uid
ORDER BY CASE WHEN table1.field1 < 11 THEN table1.field1 END ASC,
table1.field2 DESC,
table1.field3 ASC;
Explanation: 说明:
CASE table1.field1
WHEN table1.field1 < 11 THEN table1.field1
END -- this evaluates to true/false (1 and 0)
=>
CASE table1.field1 WHEN 1 THEN table1.field1 END
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