3向合并排序C程序

Question

I have trying to "upgrade" my normal merge sort for a school project. But my new code seems to not coorporate as it should

so i have a MergeSort3way function that splits the Array inputed in 3 subArrays then it call itself till the sort is finished but the outputs are far from right.

void Mergesort3way(int A[],int n){
//Sort array A with divition of 3
int B[n/3];
int C[n/3];
int D[n/3];
int i,c;

if(n>1){
    for(i=0;i<n/3;i++){
        B[i]=A[i];
    }
    for(i=n/3;i<2*n/3;i++){
        c= i-n/3;
        C[c]=A[i];
    }
    for(i=2*n/3;i<n;i++){
        c=i-(2*n/3);
        D[c]=A[i];
    }

Mergesort3way(B,n/3);
Mergesort3way(C,n/3);
Mergesort3way(D,n/3);
int bn = sizeof(B)/sizeof(B[0]);
int cn = sizeof(C)/sizeof(C[0]);
int dn = sizeof(D)/sizeof(D[0]);
Merge3way(B,C,D,A,bn,cn,dn);    
}

}

After that the merge3way combines them into 1 sigle sorted array

void Merge3way(int B[],int C[],int D[],int A[],int p,int q,int r){
int i=0,j=0,u=0,k=0;

while(i<p && j<q && u<r){
    if(B[i]<C[j]){
        if(B[i]<D[u]){
            A[k]=D[u];
            u++;
        }else{
            A[k]=B[i];
            i++;
        }
    }else{
        if(C[j]<D[u]){
          A[k]=D[u];
          u++;  
        }else{
          A[k]=C[j];
          j++;
        }
    }
    k++;
 }
int all = p+q+r;    
if(i==p){
    if(u==r){
     while(j<q && k<all){
        A[k]=C[j];
        k++;
        j++;            
     } 
    }else{
        while(u<r && k<all){
        A[k]=D[u];
        k++;
        u++;
        }
    }
}else if(j==q){
    if(u==r){
     while(i<p && k<all){
        A[k]=B[i];
        k++;
        i++;            
     } 
}
  }
} 

Can you suggest me any solution so i can sort as it should i've been trying over 2 hours of moding it and the result are always the same. Thanks in advance please no hard feeling as it is my first time using the site.

Answer 1

If this is supposed to be an ascending sort, then if (B[i] < C[j]) && (B[i] < D[u]), the code should do A[k] = B[i].

Once the end of B[], C[], or D[] is reached the code needs to switch to a 2 way merge on the remaining two. You can swap array names (which are effectively pointers in a called function), to simplify this, so the 2 way merge uses B and C. If the end of B is reached first, then B = C and C = D. If the end of C is reached first, then C = D. If the end of D is reached first, then no array (pointer) assignments are needed.

Once the end of B or C is reached, then just copy the remaining sub-array.

For consistent naming on the indices, I would have used k for D[], and u for A[], but this isn't causing a problem.

Answer 2

I think this part of your code,

while(i<p && j<q && u<r){
    if(B[i]<C[j]){
        if(B[i]<D[u]){
            A[k]=D[u];
            u++;
        }else{
            A[k]=B[i];
            i++;
        }
    }else{
        if(C[j]<D[u]){
          A[k]=D[u];
          u++;  
        }else{
          A[k]=C[j];
          j++;
        }
    }
    k++;
 }

needs to change to this:

while(i<p && j<q && u<r){
    if(B[i]<C[j]){
        if(B[i]<D[u]){
            A[k]=B[i];
            i++;
        }else{
            A[k]=D[u];
            u++;
        }
    }else{
        if(C[j]<D[u]){
          A[k]=C[j];
          j++;  
        }else{
          A[k]=D[u];
          u++;
        }
    }
    k++;
 }

And this portion of your code:

if(i==p){
    if(u==r){
     while(j<q && k<all){
        A[k]=C[j];
        k++;
        j++;            
     } 
    }else{
        while(u<r && k<all){
        A[k]=D[u];
        k++;
        u++;
        }
    }
}else if(j==q){
    if(u==r){
     while(i<p && k<all){
        A[k]=B[i];
        k++;

needs to change to something like this:

if (i < p && j < q){
  # append the result of normal merge of remaining elements of B and C to A
} else if (j < q && u < r) {
  # append the result of normal merge of remaining elements of C and D to A
} else if (i < p && u < r) {
  # append the result of normal merge of remaining elements of B and D to A
} else {
      if (i == p && j == q && u < r){
         # append remaining elements of D to A
      } else if (i < p && j == q && u == r){
         # append remaining elements of B to A
      } else if (i == p && j < q && u == r){
         # append remaining elements of C to A
      }
}

Although, as you said that you had a normal mergesort which you are trying to modify, well, how about if after sorting every 1/3 rd portion of the array, like this:

Mergesort3way(B,n/3);
Mergesort3way(C,n/3);
Mergesort3way(D,n/3);

you combine any of the two sorted portions first using normal mergesort , and then combine the result of both of them with the third portion again using normal mergesort . For example: first merge sorted B with sorted C using normal mergesort , let's call their result BmC , then merge their result BmC with sorted D using normal mergesort , leading us to final merge result: BmCmD .