Spring Boot - 映射 JSP 和 REST URI 以在控制器中处理的正确方法？

Question

I have a problem with Spring boot 1.5.2, I also added all the dependencies for JSP so it could return from web application (war) file.

application.properties

spring.mvc.view.prefix: /WEB-INF/jsp/
spring.mvc.view.suffix: .jsp

pom.xml with JSP dependencies

<!-- JSTL for JSP -->
    <dependency>
        <groupId>javax.servlet</groupId>
        <artifactId>jstl</artifactId>
    </dependency>

    <!-- Need this to compile JSP -->
    <dependency>
        <groupId>org.apache.tomcat.embed</groupId>
        <artifactId>tomcat-embed-jasper</artifactId>
        <scope>provided</scope>
    </dependency>

    <!-- Need this to compile JSP,
    tomcat-embed-jasper version is not working, no idea why -->
    <dependency>
        <groupId>org.eclipse.jdt.core.compiler</groupId>
        <artifactId>ecj</artifactId>
        <version>4.6.1</version>
        <scope>provided</scope>
    </dependency>       

And I have a simple controller like this

@Controller
public class ClassController {
    @RequestMapping("/**")
    public String handle(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
       // This one can handle any rest URIs, e.g: localhost:8080/application/abc, localhost:8080/application/abc/12/asdasd/3123,...
    }
}

However, I could not return index.jsp from localhost:8080/application/index.jsp as it will not invoke the method handle, but return

Whitelabel Error Page

This application has no explicit mapping for /error, so you are seeing this as a fallback.

Mon Oct 02 10:20:39 CEST 2017
There was an unexpected error (type=Not Found, status=404).

What is the proper configuration, so I could direct request with .jsp (eg: http://localhost:8080/application/index.jsp ) to jsp file (WEB-INF/jsp/index.jsp), and REST uri ( http://localhost:8080/application/132/21321312/324 ) to the handle method?

Answer 1

I solved this problem with using a servlet filter to forward requests containing .jsp to the corresponding files inside /WEB-INF/jsp. Other requests will go to the handle() method inside the controller.

 @WebFilter(urlPatterns = "/*")
public class SecoreFilter implements Filter {

    @Override
    public void doFilter(ServletRequest req, ServletResponse res,
            FilterChain chain) throws IOException, ServletException {

        HttpServletRequest request = (HttpServletRequest) req;
        HttpServletResponse response = (HttpServletResponse) res;
        if (!request.getRequestURI().endsWith(".jsp")) {
            chain.doFilter(req, res);
        } else {
            String jspFile = new File(request.getRequestURI()).getName();
            // e.g: /application/3223/234234/2342323/browse.jsp
            String uri = request.getRequestURI();
            // extract the jsp file from uri
            uri = uri.substring(0, uri.length() - jspFile.length());
            RequestDispatcher dispatcher = req.getServletContext()
                    .getRequestDispatcher("/WEB-INF/jsp/" + jspFile);
            req.setAttribute("uri", uri);
            dispatcher.forward(req, response);
            // chain.doFilter(req, res);
        }
    }

    @Override
    public void destroy() {
    }

    @Override
    public void init(FilterConfig arg0) throws ServletException {
    }

}

Answer 2

I've rebuilt your project based on your description and found two issues.

• tomcat-embed-jasper needs to be a compile time dependency and you don't need the Eclipse compiler
• In the controller ( ClassController ), you have to return the name of the view, which is index in your case.

You can find a working example here: https://github.com/springuni/springuni-stackoverflow/tree/master/question-46521912

What it does is that it redirects any given request (/application/132/21321312/324) to index.jsp . In the JSP the path of the request is written to the output for demonstrating that the redirection actually came from the controller.

Let me know if it worked for you!

Cheers, László