.NET自定义配置：使用文化区域不变/ XML格式序列化DateTimeOffest属性？

Question

I'm using a custom configuration section within an MVC web application I'm currently working on. Given the following property MyProperty of type System.DateTimeOffset within a custom ConfigurationElement implementation:

public class MyClass : ConfigurationElement
{
    /// other properties...

    [ConfigurationProperty("myDateProperty", IsRequired = true)]
    public DateTimeOffset MyDateProperty
    {
        get
        {
            return (DateTimeOffset)this["myDateProperty"];
        }

        set
        {
            this["myDateProperty"] = value;
        }
    }
}

Could anyone explain why this gets serialized within the config file using (presumably) the en-US culture, like so:

    <add key="..." myDateProperty="10/02/2017 12:19:38 +01:00" />

I would have hoped the value would have be serialized in a culture-invariant format or XML format, eg:

    <add key="..." myDateProperty="2017-10-02T12:19:38+01:00" />

How can I specify a culture-invariant / XML format for serializing date-related properties?

Additional details which may or may not be important:

• I'm writing the values to a separate config file (referenced within web.config );
• The target .NET Framework is v4;
• The application's Thread.CurrentCulture and Thread.CurrentUICulture are both set (implicitly) to en-GB ;
• The same issue also occurs if I change the type to System.DateTime .

Answer 1

For me works fine:

Thread.CurrentThread.CurrentCulture = new MyCultureInfo(CultureInfo.InvariantCulture.Name);

MyDateTimeFormat:

public class MyCultureInfo : CultureInfo
{
    ......implement constructors       

    private DateTimeFormatInfo dateTimeFormatInfo;
    public override DateTimeFormatInfo DateTimeFormat {
        get
        {
            if (dateTimeFormatInfo == null)
            {
                var dateTimeFormatInfo = new DateTimeFormatInfo();
                dateTimeFormatInfo.FullDateTimePattern = "yyyy-MM-ddTHH:mm:ssK";
                dateTimeFormatInfo.LongTimePattern = "yyyy-MM-ddTHH:mm:ssK";
            }
            return dateTimeFormatInfo;
        }
    }
}