[英]Create a list from Tibble Columns
I have a tibble like this: 我有这样的小标题:
> library(tidyverse)
> tbl <- tibble(x = c('a', 'b', 'c'), y = 1:3)
> tbl
# A tibble: 3 x 2
x y
<chr> <int>
1 a 1
2 b 2
3 c 3
I would like to create a list where the names of the elements of the list are those from x (I have all distinct entries) and the values are those from y. 我想创建一个列表,其中列表元素的名称是x的名称(我有所有不同的条目),值是y的名称。 I would like this list:
我想要这个清单:
list(a = 1, b = 2, c = 3)
$a
[1] 1
$b
[1] 2
$c
[1] 3
Thank you in advance 先感谢您
You can convert column y to a list, and setNames
with column x : 您可以将y列转换为列表,并将
setNames
转换为x :
setNames(as.list(tbl$y), tbl$x)
#$a
#[1] 1
#$b
#[1] 2
#$c
#[1] 3
using tidyr
使用
tidyr
library(tidyr)
tbl <- tibble(x = c('a', 'b', 'c'), y = 1:3)
as.list(spread(tbl, x, y))
spread
takes the long format data and makes it wide, then converting it to a list gives the desired output. spread
采用长格式的数据并使其变宽,然后将其转换为列表可提供所需的输出。
# $a
# [1] 1
#
# $b
# [1] 2
#
# $c
# [1] 3
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