使用Ramda的功能组合

Question

I have a 2 functions and 1 variable which when combined take the form

const value = f(g(x))(x)

That is, f(g(x)) returns a function taking x again. I don't like this redundancy and it's preventing me from declaring my function pointfree.

What Ramda function do I need to transform this into R.something(f, g)(x)?

Here's a working example, testable in http://ramdajs.com/repl/?v=0.24.1 ,

const triple = x => x * 3
const conc = x => y => x + " & " + y

const x = 10

conc(triple(x))(x)

// I'm looking for R.something(conc, triple)(x)

Answer 1

You can use R.chain

const something = chain(conc, triple)

You can see this in action on the Ramda repl .

Answer 2

you can make a function result which does

 const triple = x => x * 3 const conc = x => y => x + " & " + y let result = (a, b) => e => a(b(e))(e) const x = 10 console.log(conc(triple(x))(x)); // I'm looking for R.something(conc, triple)(x) console.log(result(conc, triple)(x));