如何将两个列表合并为第三个列表？

Question

I got three list of lists:

A=[[9, 'a'], [0, 'c'], [2, 'g'], [7, 'w'], [0, 'Q']]
B=[[0, 'a'], [0, 'c'], [0, 'w'], [0, 'Q'], [3, 'front'], [5, 'Z']]
C=[[9, 'a'], [0, 'c'], [7, 'w'], [0, 'Q']]

and I want to combine A and B into C like this:

C=[[9, 'a'], [0, 'c'],[7, 'w'], [0, 'Q'],[2,'g'], [3,'front'],[5,'Z']] 

Basically list with g is not in C so I append into C.Same for list B.

EDIT:I do not need a specific index just append into C.The output is just an example output.It can be in any order.

Answer 1

If I understood the question correctly, it sounds like you want to add to C values from A and B that were not already in it, making a set of unique values? If so, this is the way to go:

C = [list(x) for x in set(tuple(x) for x in A+B+C)]

Answer 2

from itertools import zip_longest
for x,y in zip_longest(enumerate(A),enumerate(B)):
    for i in x,y:
        if i is not None and i[1][1] not in map(lambda i: i[1], C):
            if(i[0] < len(C)):
                C.insert(i[0], i[1])
            else:
                C.append(i[1])
print(C)

In order to have the location data as you outlined, this approach seems to work. It's output is: [[3, 'front'], [5, 'Z'], [7, 'w'], [0, 'Q'], [0, 'c'], [0, 'w'], [9, 'a'], [2, 'g'], [0, 'a']]