[英]Python replace backward (\) with forward (/)
I am trying to replace \\
with /
. 我正在尝试用
/
替换\\
。 However, I'm having no success. 但是,我没有成功。 Following is the snapshot of the scenario that I am trying to achieve
以下是我尝试实现的场景的快照
string = "//SQL-SERVER/Lacie/City of X/Linservo\171002"
print string.replace("\\","/")
Output: 输出:
//SQL-SERVER/Lacie/City of X/Linservoy002
Desired output: 所需的输出:
//SQL-SERVER/Lacie/City of X/Linservo/171002
You need to escape "\\" with an extra "\\". 您需要使用额外的“ \\”转义“ \\”。
>>> string = "//SQL-SERVER/Lacie/City of X/Linservo\\171002"
>>> string
'//SQL-SERVER/Lacie/City of X/Linservo\\171002'
>>> print string.replace("\\","/")
//SQL-SERVER/Lacie/City of X/Linservo/171002
string = r"//SQL-SERVER/Lacie/City of X/Linservo\171002"
print string.replace("\\","/")
output 输出
//SQL-SERVER/Lacie/City of X/Linservo/171002
You have errors both in replace function and in string definition. 您在替换函数和字符串定义中均存在错误。
\\171
gives char with octal value of 171 – y \\171
为char提供八进制值171 – y You should escape backslashes 您应该转义反斜杠
string = "//SQL-SERVER/Lacie/City of X/Linservo\\171002"
string.replace("\\","/")
You can simply use ".replace" in python or if you want you can use regex : 您可以在python中简单地使用“ .replace”,也可以使用regex:
import re
string = r"//SQL-SERVER/Lacie/City of X/Linservo\171002"
pattern=r'[\\]'
replaced_string=re.sub(pattern,"/",string)
print(replaced_string)
Since your original question shows : "X/Linservo\\171002"
here \\171
referring to character encoding so it's replacing \\171
to "y"
. 由于您的原始问题显示:
"X/Linservo\\171002"
这里\\171
指的是字符编码,因此它将\\171
替换为"y"
。 you can try this in python interpreter : 您可以在python解释器中尝试此操作:
In[2]: print("\171")
y
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.