UnboundLocalError: TRY EXCEPT STATEMENTS

Question

I am currently creating a menu with try except tools. I'm trying to create it so if a user enters nothing (presses ENTER) to output:

You have not entered anything, please enter a number between 1 and 4

This is what I've done so far:

def Menu():
    print("""
    Hello, please enter a number 1 - 4
        1 - Compliment
        2 - Fact
        3 - Insult
        4 - Quit
        """)
    try:
        UserInput_INT = int(input("> "))

    except ValueError:
        UserInput_STR = (UserInput_INT)

        if len(UserInput_STR) == 0:
            print("You have entered nothing. Please enter a number between 1 and 4")

        print("You entered a character. Please enter a number between 1 and 4")
        Menu()

    if UserInput_INT not in range (1, 5):
        print("Invalid input please enter a whole number between 1 and 4")


    UserInput_STR = (str(UserInput_INT))

    if UserInput_STR == '1':
        print(" You look horrible today!")

    elif UserInput_STR == '2':
        print("Sam Birkenshaw & Jordan Ives can code better than Mr Bath. ")

    elif UserInput_STR == '3':
        print("You are bad at coding ")

    elif UserInput_STR == '4':
        quit()

Menu()

Answer 1

Try this and its same as you expected your output to be.

 UserInput=input("> ")
 try:
    UserInput_INT = int(UserInput)

So here we first input into UserInput_INT and then in the try block we cast it to integer type.

Answer 2

In the statement UserInput_STR = (UserInput_INT) [*] you are accessing a variable that you did not initalize, since int(input("> ")) have failed. Here's a shorter example:

def f():
    try:
        x = 2/0
    except:
        print(x)

What should print(x) do? the variable is indeed local, but is not bound. It is not initialized.

[*] I believe you meant something like UserInput_STR = str(UserInput_INT) , but it won't work either for the same reason.