如何格式化函数以调用模板化类？

Question

I'm sure there is a very easy answer, but I can't figure it out. I have written a templated class, but I want to pass that class by reference in a class function that isn't templated. Heres what I have. I get a bunch of errors. All I need to do is figure how to format the way to insert templated class into function, but I'm at a lost. Thank you and sorry if the code doesn't really help you out.

#include <iostream>
using namespace std;

template <typename T>
class Foo {
public:
    Foo();
    insert(const T& Item)
    //And other function, just examples
};

class noFoo(){
void test(Foo <T>& foo);
int i;
int j;
int k
};

template <typename T>
void noFoo::test(Food <T>& foo)}
cout << "hi";
}
int main() {
    Foo<char> wr;
    test(wr);
    return 0;
}

Answer 1

Make test a function template. I also corrected loads of syntax errors for you ( class noFoo() ?), removed unnecessary code, and ran clang-format for indentation.

#include <iostream>

template <typename T>
class Foo {};

class noFoo
{
public:
    template <typename T>
    void test(Foo<T> &);
};

template <typename T>
void noFoo::test(Foo<T> &)
{
    std::cout << "hi\n";
}

int main()
{
    Foo<char> wr;
    noFoo{}.test(wr);
}

---

Since your question is tagged d , here the same code in D.

import std.stdio;

class Foo(T) {};

class noFoo
{
public:
    void test(T)(Foo!(T))
    {
        writeln("hi");
    }
};

void main()
{
    auto wr = new Foo!char;
    (new noFoo).test(wr);
}