[英]Get parameter from ajax to controller Laravel
I want to pass value of id to controller in Laravel我想将 id 的值传递给 Laravel 中的控制器
my Ajax Code:我的 Ajax 代码:
$(document).ready(function () {
$(document).on('click', '.brnch_clk', function () {
//alert('ok')
var branchid = $(this).data('branch');
$('#txt_branchid').val(branchid);
alert($(this).data('branch'));
$.ajax({
'url': 'search',
'type': 'GET',
'data': {id: branchid},
success: function(response){ // What to do if we succeed
if(data == "success")
alert(response);
},
error: function(response){
alert('Error'+response);
}
});
});
});
My Controller:我的控制器:
public function search(Request $request)
{
$member = $request->get('id');
return json_encode($member);
}
My Route:我的路线:
Route::get('search', 'ShowstaffController@search');
My Link:我的链接:
<a href="{{URL('search')}}" class="brnch_clk"
data-branch="{{$value->branch_id}}"> {{$value->Branch_Name}}
</a>
How can i get parametter id from ajax to controller??如何从ajax获取参数ID到控制器?
You can not send GET
value in data
.您不能在
data
发送GET
值。 Send it in the URL
as a query string.在
URL
中将其作为查询字符串发送。 Check this code:检查此代码:
$(document).ready(function () {
$(document).on('click', '.brnch_clk', function (e) {
e.preventDefault();
//alert('ok')
var branchid = $(this).data('branch');
$('#txt_branchid').val(branchid);
//alert($(this).data('branch'));
$.ajax({
'url': 'search?id='+branchid,
'type': 'GET',
'data': {},
success: function(response){ // What to do if we succeed
if(data == "success")
alert(response);
},
error: function(response){
alert('Error'+response);
}
});
});
});
您应该使用query
方法从query string
获取参数。
$request->query('id');
I suppose 'url': 'search?id='+branchid
in place of 'url': 'search'
should force JQuery to send data
as GET parameters.我想
'url': 'search?id='+branchid
代替'url': 'search'
应该强制 JQuery 将data
作为 GET 参数发送。 Otherwise, data is sent as POST parameters.否则,数据将作为 POST 参数发送。
The same thing happened to me, I used all solutions, but could not get the result.同样的事情发生在我身上,我使用了所有解决方案,但无法得到结果。
Here what I did,这是我所做的,
Here jQuery Snippet这里是 jQuery 代码段
var branchid = $(this).data('branch');
var form = new formData();
form.append('id',branchid)
$.ajax({
'url': 'search',
'type': 'GET',
'data': form,
success: function(response){ // What to do if we succeed
if(data == "success")
alert(response);
},
error: function(response){
alert('Error'+response);
}
});
Laravel Controller Laravel 控制器
public function search(Request $request)
{
$id = $request->get('id');
}
NOTE: You don't need to encode json, Laravel by default send response in JSON format.注意:您不需要编码 json,Laravel 默认以 JSON 格式发送响应。
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