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多维 ruby​​ 数组:是否可以用多个参数定义 [] 运算符?

[英]Multidimensional ruby array: Is it possible to define the []-operator with more than one argument?

I want to implement a table datastructure.我想实现一个表数据结构。 Maybe you can recommend a better alternative, but as Ruby doesn't provide built-in support for multidimensional arrays, the nearest solution is using a Hash and an Array as index也许您可以推荐一个更好的替代方案,但由于 Ruby 不提供对多维数组的内置支持,因此最近的解决方案是使用 Hash 和 Array 作为索引

pseudoTable = Hash.new
pseudoTable[[0,"id"]] = 23
pseudoTable[[0,"name"]] = "Hans"

Now I tried the following现在我尝试了以下

class MyTable
  attr_accessor :id, :table_hash
  def [](a,b)
    @table_hash[[a,b]]
  end
end

So, isn't it possible in Ruby to give two arguments to def []() ?那么,在 Ruby 中是否可以为def []()提供两个参数?

If not, can you recommend another approach (a built-in datastructure than Hash, etc. better suited) to implement a table capable of dynamic extension and bonus points for being sequentially iterable?如果没有,您能否推荐另一种方法(比 Hash 更适合的内置数据结构等)来实现一个能够动态扩展的表和顺序迭代的奖励积分?

Is this the behavior you're looking for?这是您正在寻找的行为吗?

class MyTable
  def initialize()
    @table = Hash.new
  end

  def [](a, b)
    return nil if @table[a].nil?
    @table[a][b]
  end

  def []=(a, b, c)
    @table[a] ||= {}
    @table[a][b] = c
  end
end

usage:用法:

2.4.1 :038 > a = MyTable.new
 => #<MyTable:0x007faf6f9161c8 @table={}>
2.4.1 :039 > a[0,0]
 => nil
2.4.1 :040 > a[0,0] = 1
 => 1
2.4.1 :041 > a[0,0]
 => 1

I'm pretty confident there are better ways to do this, and this solution might contain some bugs, but hopefully it demonstrates how to define and use multi-argument [] and []= methods.我非常有信心有更好的方法来做到这一点,这个解决方案可能包含一些错误,但希望它展示了如何定义和使用多参数[][]=方法。

You can try to use ruby-numo library您可以尝试使用ruby-numo 库

apt install -y git ruby gcc ruby-dev rake make
gem install specific_install
gem specific_install https://github.com/ruby-numo/narray.git

irb

arr = Numo::Narray[[1], [1, 2], [1, 2, 3]]

 => Numo::Int32#shape=[3,3]
[[1, 0, 0],
 [1, 2, 0],
 [1, 2, 3]]

arr[0, 0]
 => 1

arr[0, 1]
 => 0

arr[0, 2]
 => 0

arr[0, 3]
IndexError: index=3 out of shape[1]=3    

You can learn more detailed documentation there您可以在那里了解更详细的文档

What you did would work fine, the trouble is that @table_hash is not recognised as a hash.你所做的会正常工作,问题是@table_hash不被识别为哈希。 You need to initialize it as such.您需要像这样初始化它。

class MyTable
  attr_accessor :id, :table_hash

  def initialize(*args)
    @table_hash = Hash.new
    super
  end

  def [](a,b)
    @table_hash[[a,b]]
  end
end

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