遍历javascript中的整数，其中每个值都等于一个数字

Question

I would like to use the $.each() loop to iterate over digits in an integer. The integer is produced as the index of another array, though I'm not sure that this makes a difference.

Javascript

var words = [ "This", "is", "an", "array", "of", "words","with", "a", "length", "greater", "than", "ten." ];
var numbers = [];
$.each(words, function(i,word) {
    $.each(i, function(index,value) {
        $(numbers).append(value);
    });
});

I would like the array numbers to equal the following array:

[ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 1, 0, 1, 1 ]

Where the last four entries, [ ... 1, 0, 1, 1 ] are generated through iteration over the indexes for the entries [ ... "than", "ten." ] [ ... "than", "ten." ] in the words array.

Answer 1

 let words = [ "This", "is", "an", "array", "of", "words","with", "a", "length", "greater", "than", "ten." ]; let numbers = words.map((w, i) => i.toString().split('').map(Number)) //map into array of digits numbers = Array.prototype.concat.call(...numbers); //concat them all console.log(numbers);