Python-根据今天开始在一周的第一天，最后一天了解TimeZone

Question

I want to get first, last day of the week based on users current timezone. i am trying to solve but i could not find a way move forward to solve in python.here i have taken two diff timezones for example.

from datetime import datetime, date, timedelta
from pytz import timezone

tz1 = timezone('utc')
tz2 = timezone('Asia/Kolkata')
tz3 = timezone('America/Los_Angeles')

dt1 = datetime.now(tz=tz1)
dt2 = datetime.now(tz=tz2)
dt3 = datetime.now(tz=tz3)


start_of_week = dt1+timedelta(days=0-dt1.weekday())
end_of_week = dt1+timedelta(days=6-dt1.weekday())

print(start_of_week)
print(end_of_week)

start_of_week2 = dt2+timedelta(days=0-dt2.weekday())
end_of_week2 = dt2+timedelta(days=6-dt2.weekday())

print(start_of_week2)
print(end_of_week2)


start_of_week3 = dt3+timedelta(days=0-dt3.weekday())
end_of_week3 = dt3+timedelta(days=6-dt3.weekday())

print(start_of_week3)
print(end_of_week3)

Output:

2017-10-02 09:21:32.666920+00:00
2017-10-08 09:21:32.666920+00:00
2017-10-02 14:51:32.666920+05:30 # not right
2017-10-08 14:51:32.666920+05:30 # not right
2017-10-02 02:21:32.666920-07:00 # not right
2017-10-08 02:21:32.666920-07:00 # not right

I live in Asia/kolkata and start of the week Oct 01 (Sunday) and end of the week Oct 07 (Saturday) , what is wrong here?

Answer 1

Extending your code:

from datetime import datetime, date,timedelta
from pytz import timezone

tz1 = timezone('utc')
tz2 = timezone('Asia/Kolkata')
tz3 = timezone('America/Los_Angeles')

dt1 = datetime.now(tz=tz1)
dt2 = datetime.now(tz=tz2)
print(dt1)
print(dt2)

start_of_week = dt1+timedelta(days=0-dt1.weekday())
end_of_week = dt1+timedelta(days=6-dt1.weekday())

print(start_of_week)
print(end_of_week)

Answer 2

I'm expanding chakris answer:

updated Since a week either can start or end on the same day, when you input sunday and the week start with sunday you have two options.

Maybe you can change the code to fit your needs.

from datetime import datetime, date,timedelta
from pytz import timezone

def week_startandend(dt_,weekstart=0):
    """Returns tuple with start date of week and end day of week."""
    index = (dt_.weekday() + (7-weekstart % 7) ) % 7

    # Calculate start and end
    start = dt_+timedelta(days=0-index)
    end  = dt_+timedelta(days=6-index)

    # if week doesnt start on the same day we can return
    if index != 0:
        return {"start":start.date(),"end":end.date()}
    # else we need to calculate the other option
    else:
        start2 = dt_+timedelta(days=-7)
        end2 = dt_
        return {"start1":start.date(),"end1":end.date(),
                "start2":start2.date(),"end2":end2.date()}

tz1 = timezone('utc')
tz2 = timezone('Asia/Kolkata')

dt1 = datetime.now(tz=tz1)
dt2 = datetime.now(tz=tz2)

print(week_startandend(dt1)) # defaults to 0
print(week_startandend(dt2,weekstart=6)) # 6 = sunday

Returns

{'start': datetime.date(2017, 10, 2), 'end': datetime.date(2017, 10, 8)}
{'start1': datetime.date(2017, 10, 8), 'end1': datetime.date(2017, 10, 14),
'start2': datetime.date(2017, 10, 1), 'end2': datetime.date(2017, 10, 8)}

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