Gulp-uglify不产生缩小的输出文件

Question

I've been trying to minify my js files, but I can't get gulp to produce an output file. To keep things simple, I created a test.js file in my root directory, and I'm trying to get gulp to compress and send a minified file to my public folder. I've been banging my head on this one for a while, so thanks in advance! Here's my app.js file

var gulp = require('gulp');
var uglify = require('gulp-uglify');
var pump = require('pump');

var app = express();

// view engine setup
app.set('views', path.join(__dirname, 'app_server', 'views'));
app.set('view engine', 'jade');

gulp.task('compress', function(cb) {
  pump([
      gulp.src('./test.js'),
      uglify(),
      gulp.dest('./public')
    ],
    cb
  );
}); 

My test.js file

var myFunc = function(aa, bb) {
    return aa + bb;
};

myFunc(1, 2);

And my dependencies

  "devDependencies": {
    "gulp": "^3.9.1",
    "gulp-uglify": "^3.0.0",
    "pump": "^1.0.2"
  }

Answer 1

I figured it out, I just had to install gulp globally, create a gulpFile.js in my root directory, and insert this content in the file:

var gulp = require('gulp');
var uglify = require('gulp-uglify');
var concat = require('gulp-concat');
var watch = require('gulp-watch');
var pump = require('pump');

gulp.task('stream', function() {
    return watch('app_client/**/*.js', function() {
        pump([
            gulp.src([
                'app_client/app.js',
                'app_client/home/home.controller.js'
            ]),
              concat('loc8r.min.js'),
              uglify(),
              gulp.dest('./public/angular')
            ]
        );
    });
}); 

Then in the root directory, head over to the command line and run

gulp stream

This method deals with all error handling and automates the process so you don't have to use the CLI every time you update a js file