模式与Java中的2个中间数字匹配

Question

I want third pattern ([0-9]{2}) should less than 10 or 10. I've also tried with [1-9]|0[0-9]|1[0-0] pattern instead of [0-9]{2} but unable to get the solution. I want result in following format: 012 550 10 0123456 01.

public static void main(String args[]){         
            System.out.println(Pattern.matches("[0-9]{3}[550]{3}[0-9]{2}[0-9]{6}[01]{2}", "8035501002499901")); 
}

Answer 1

From your question it seems as if the pattern you want is this:

• any 3 digits ( [0-9]{3} )
• 550 fixed ( 550 ) - note that [550]{3} would mean any sequence of 3 digits that are either 5 or 0, eg 005, 050, 555, etc.
• 2 digits which either should be 0x or 10 ( (?:0[0-9]|10) )
• any 6 digits ( [0-9]{6} )
• 01 fixed ( 01 ) - [01]{2} would mean any sequence of 2 digits that are either 0 or 1, eg 00, 01, 10 and 11 all would match

Thus the regex you'd need would be:

[0-9]{3}550(?:0[0-9]|10)[0-9]{6}01