删除bash变量中所有出现的单词

Question

i have a variable like this: (each word in a new line)

> echo $LIST
toto
toto2
titi
rererer
dfs
sdfsdf
titi
titi

I try to remove all occurences of "titi" to obtain that:

> echo $LIST
toto
toto2
rererer
dfs
sdfsdf

i tried with LIST=$(echo ${LIST//titi/}) and it remove it but it also delete new line and give this result:

> echo $LIST
toto toto2 rererer dfs sdfsdf

My question is how to remove all occurences keeping each word in a line ? Thanks in advance :)

Answer 1

You need to put quotes around "${LIST//titi/}" , otherwise whitespace will be collapsed:

$ LIST='toto
> toto2
> titi
> rererer
> dfs
> sdfsdf
> titi
> titi'
$ echo "${LIST//titi/}"
toto
toto2

rererer
dfs
sdfsdf

But you can also just assign directly:

LIST=${LIST//titi/}
echo "$LIST" # quotes are important here!