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将具有不同元素的 XML 反序列化为分隔列表

[英]Deserialize XML with different elements to separated lists

Could you please help me with deserialization of current xml:你能帮我反序列化当前的xml吗:

<ObjectList>
  <Item Attr1="1"/>
  <Item Attr1="2"/>
  <DifferentItem Attr2="5"/>    
</ObjectList>

I want to deserialize it in structure like this我想在这样的结构中反序列化它

public class ObjectList
{
    public List<Item> Items { get; set; }
    public List<DifferentItem> DifferentItems { get; set; }
}

public class Item
{
    public string Attr1 { get; set; }
}

public class DifferentItem
{
    public string Attr2 { get; set; }
}

I tried attributes, but unsuccessfully我尝试了属性,但没有成功

[XmlArray("ObjectList")]
[XmlArrayItem("Item", typeof(Item))]

How can I solve this?我该如何解决这个问题? Thanks)谢谢)

Add attributes:添加属性:

public class ObjectList
{
    [XmlElement("Item")]
    public List<Item> Items { get; set; }
    [XmlElement("DifferentItem")]
    public List<DifferentItem> DifferentItems { get; set; }
}

You need to use XML attributes to help map XML to classes and properties.您需要使用 XML 属性来帮助将 XML 映射到类和属性。 Here's a console app I wrote with your XML, and it gets parsed OK.这是我用你的 XML 编写的控制台应用程序,它被解析为 OK。 Notice how I used the XmlRoot and XmlElement attributes to map it.请注意我如何使用 XmlRoot 和 XmlElement 属性来映射它。

public class Program
{
    public static void Main()
    {
        var serializer = new XmlSerializer(typeof(ObjectList));
        var xml = "<ObjectList><Item Attr1=\"1\" /><Item Attr1=\"2\" /><DifferentItem Attr2=\"5\" /></ObjectList>";

        using (var reader = new StringReader(xml))
        {
            var schedule = (ObjectList)serializer.Deserialize(reader);
        }
    }

    [XmlRoot("ObjectList")]
    public class ObjectList
    {
        [XmlElement("Item")]
        public List<Item> Items { get; set; }

        [XmlElement("DifferentItem")]
        public List<DifferentItem> DifferentItems { get; set; }
    }

    public class Item
    {
        [XmlAttribute("Attr1")]
        public string Attr1 { get; set; }
    }


    public class DifferentItem
    {
        [XmlAttribute("Attr2")]
        public string Attr2 { get; set; }
    }
}

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