[英]Java- Moving elements from a ArrayList to an Array
I currently have a randomly mixed ArrayList
. 我目前有一个随机混合的
ArrayList
。
public static void main(String[] args) {
ArrayList<Integer> solution = new ArrayList<>();
for (int i = 1; i <= 48; i++) {
solution.add(i);
}
Collections.shuffle(solution);
This gives me a ArrayList
with the numbers 1-48 randomly mixed. 这给了我一个1-4随机混合的数字的
ArrayList
。 Now I have 4 arrays and I want to randomly add the elements of the ArrayList
with out repetition. 现在我有4个数组,我想不加重复地随机添加
ArrayList
的元素。
int[] heartsRow = new int[14];
int[] diamondsRow = new int[14];
int[] spadesRow = new int[14];
int[] clubsRow = new int[14];
The reason the new arrays contain 14 elements is because the first two elements will always be the same. 新数组包含14个元素的原因是,前两个元素将始终相同。
heartsRow[0] = 1;
heartsRow[1] = 0;
diamondsRow[0] = 14;
diamondsRow[1] = 0;
spadesRow[0] = 27;
spadesRow[1] =0;
clubsRow[0] = 40;
clubsRow[1] = 0;
I want to completely fill each array with non-repeating elements of the ArrayList
. 我想用
ArrayList
非重复元素完全填充每个数组。
You could use a counting loop over the list, increment the counter by 4 in each step, and assign elements to the arrays with adjusted offsets: 您可以在列表上使用计数循环,在每个步骤中将计数器增加4,然后将元素分配给具有调整偏移量的数组:
for (int i = 0; i + 3 < solution.size(); i += 4) {
int j = i / 4;
heartsRow[2 + j] = solution.get(i);
diamondsRow[2 + j] = solution.get(i + 1);
spadesRow[2 + j] = solution.get(i + 2);
clubsRow[2 + j] = solution.get(i + 3);
}
You can make 4 for loops, from 0 to 11, 12 to 23, 24 to 35 and 36 to 47, and add in your lists. 您可以创建4个for循环,从0到11、12到23、24到35和36到47,然后添加到列表中。
for (int i = 0; i < 12; i++)
heartsRow[i + 2] = solution.get(i);
for (int i = 0; i < 12; i++)
diamondsRow[i + 2] = solution.get(i + 12);
for (int i = 0; i < 12; i++)
spadesRow[i + 2] = solution.get(i + 24);
for (int i = 0; i < 12; i++)
clubsRow[i + 2] = solution.get(i + 36);
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