Python Regex排除某些前缀

Question

Given the following string

s = '"foo" "bar2baz_foo" foo( bar2baz_foo( p_foo p_foo.'

I need a regex such that

re.findall(regex, s)

gives

['foo', 'bar2baz_foo', 'foo', 'bar2baz_foo']

So it matches the first four "words" excluding the quotes and parentheses but not the last two. I have tried a couple different things but nothing I can come up with actually works.

Hope someone here can help.

Edit: I should add that I want to replace the results with something else and not just find it, ie I wanna use re.sub and not re.findall . And also the string is the content of a text file in reality and therefore much longer. I just extracted the relevant bits.

Answer 1

If you're not hell-bent on a pure regex solution, you could use The Greatest Regex Trick Ever .

>>> s = '"foo" "bar2baz_foo" foo( bar2baz_foo( p_foo p_foo.'
>>> import re
>>> filter(None, re.findall(r'p_\w*|(\w+)', s))
['foo', 'bar2baz_foo', 'foo', 'bar2baz_foo']

Small demo for usage in re.sub :

>>> re.sub(r'p_\w*|(\w+)', lambda m: 'WORD' if m.group(1) else m.group(), s)
'"WORD" "WORD" WORD( WORD( p_foo p_foo.'