[英]Qt: remove model from view
We usually set view's model in Qt like this: view->setModel(model);
我们通常像这样在Qt中设置视图的模型:
view->setModel(model);
But is there any way to remove a model from view? 但是,有什么方法可以从视图中删除模型吗? I mean literally leave a view empty like it was just created and there was not any model set to it yet.
我的意思是说,将视图保留为空,就像刚刚创建的那样,并且尚未设置任何模型。
If you ask me a reason of my desire, I have a pretty much similar case as in this guy's post . 如果您问我一个求婚的理由 ,那么我的情况与这个人的帖子非常相似。 And when first view has no selection or it is empty/invalid/whatever, I want to make the second view show literally nothing: no headers, columns, rubbish data.
当第一个视图没有选择或者它是空的/无效的/什么的时候,我想让第二个视图实际上不显示任何内容:没有标题,列,垃圾数据。 Removing a model from the view seems to be pretty reasonable in that case.
在这种情况下,从视图中删除模型似乎非常合理。
I've tried a dirty hack: *view = QTableView();
我尝试了一个肮脏的hack:
*view = QTableView();
But Qt took care about such evil things and made operator=
private. 但是Qt照顾了这些邪恶的事情,并把
operator=
私有了。
From the source of QAbstractItemView::setModel()
: 从
QAbstractItemView::setModel()
的源:
d->model = (model ? model : QAbstractItemModelPrivate::staticEmptyModel());
It looks like if you pass a null pointer, it will internally use some dummy model fallback. 看起来,如果您传递空指针,它将在内部使用一些虚拟模型回退。 So null pointers are supported and that's a valid way to go to "unset" the current model.
因此,支持空指针,这是“重置”当前模型的有效方法。
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