将双箭头转换为标准功能

Question

While reading the following article: https://medium.com/javascript-scene/master-the-javascript-interview-what-is-a-pure-function-d1c076bec976 and I got to the following piece of code:

const highpass = (cutoff, value) => value >= cutoff;

Which outputs:

highpass(5, 123); // true
highpass(5, 5);   // true
highpass(5, 1);   // false

Since I'm not an expert on fat arrow function I tried to convert them into simple functions, but the second fat arrow and the result are confusing me, here's what I have so far:

function highpass(cutoff, value)
{
    return function(value)
    {
        return function(cutoff)
        {
            ????????
        }
    };
};

What am I missing here?

Answer 1

That is equivalent to

 const highpass = function(cutoff, value){ return value >= cutoff; } console.log(highpass(2, 3)) 

Answer 2

在Question的代码中只有一个箭头函数， >= 大于或等于运算符

function highpasss(value, cutoff) {return value >= cutoff}

Answer 3

The "second" is a comparison, not a function

const highpass = (cutoff, value) => value >= cutoff;

translates to

const highpass = function(cutoff, value) {
    return value >= cutoff;
}