使用 python 重命名文件夹中的文件名列表

Question

I have a list of WAV files in a folder of data showing in the format of hours, minutes and second.

For example,

C:\Users\Desktop\Data

01h02m02s.wav
01h02m13s.wav
01h02m24s.wav

I need the filename to be modified, programmatically such that it needs to be converted into seconds. How do I do it?

3722s.wav
3733s.wav
3744s.wav

Would appreciate all feedback and help.

Thank you

Answer 1

Use glob.glob() to get your file list and then an regular expression to try and extract the hours , minutes and seconds from the filename. os.rename() is used to actually rename the file:

import glob
import re
import os

path = r'C:\Users\Desktop\Data'

for wav in glob.glob(os.path.join(path, '*.wav')):
    re_hms = re.findall(r'(\d+)h(\d+)m(\d+)s\.wav', wav)

    if re_hms:
        hours, minutes, seconds = map(int, re_hms[0])
        total_seconds = hours * 3600 + minutes * 60 + seconds
        new_wav = os.path.join(path, '{}s.wav'.format(total_seconds))
        print "{} -> {}".format(wav, new_wav)
        os.rename(wav, new_wav)

os.path.join() is used to safely join file paths together without having to worry about adding path separators.

Answer 2

You could use this if all the files in the path are WAV and their names have the pattern as shown by you.

import os

path = r'C:\Users\Desktop\Data'
waves = os.listdir(path)

for wave in waves:
    hours, minutes, seconds = map(int, [wave[:2], wave[3:5], wave[6:8]])
    total_seconds = hours * 3600 + minutes * 60 + seconds
    new_name = os.path.join(path, "{}s.wav".format(total_seconds))

    os.rename(os.path.join(path, wave), new_name)