如何检查数组是否包含至少一个对象？

Question

I want to check if array contains object or not. I am not trying to compare values just want to check in my array if object is present or not?

Ex.

$arr = ['a','b','c'] // normal
$arr = [{ id: 1}, {id: 2}] // array of objects
$arr = [{id: 1}, {id:2}, 'a', 'b'] // mix values

So how can i check if array contains object

Answer 1

You can use some method which tests whether at least one element in the array passes the test implemented by the provided function.

 let arr = [{id: 1}, {id:2}, 'a', 'b']; let exists = arr.some(a => typeof a == 'object'); console.log(exists); 

Answer 2

I want to check if array contains object or not

Use some to simply check if any item of the array has value of type "object"

var hasObject = $arr.some( function(val){
   return typeof val == "object";
});

Answer 3

 var hasObject = function(arr) { for (var i=0; i<arr.length; i++) { if (typeof arr[i] == 'object') { return true; } } return false; }; console.log(hasObject(['a','b','c'])); console.log(hasObject([{ id: 1}, {id: 2}])); console.log(hasObject([{id: 1}, {id:2}, 'a', 'b'])); 

Answer 4

You could count the objects and use it for one of the three types to return.

 function getType(array) { var count = array.reduce(function (r, a) { return r + (typeof a === 'object'); }, 0); return count === array.length ? 'array of objects' : count ? 'mix values' : 'normal'; } console.log([ ['a', 'b', 'c'], [{ id: 1 }, { id: 2 }], [{ id: 1 }, { id: 2 }, 'a', 'b'] ].map(getType)); 

Answer 5

对数组进行类型检查

const hasObject = a => Array.isArray(a) && a.some(val => typeof val === 'object')