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C ++如何正确复制指针的容器(向量)?

[英]C++ How to properly copy container(vector) of pointers?

A few times I've stumbled across the scenario where I have a container of pointers that needs to be copied. 有几次我偶然发现了我有一个需要复制的指针容器的场景。

Let's say we have the following class hierarchy: 假设我们有以下类层次结构:

  • Student (base class) 学生(基础班)

    • Freshman (subclass) 新生(子类)
    • Sophmore (subclass) Sophmore(子类)
    • Junior (subclass) 少年(子类)
    • Senior (subclass) 高级(子类)
  • StudentService StudentService

The StudentService class has a std::vector<Student*> students field and the following constructor: StudentService类有一个std::vector<Student*> students字段和以下构造函数:

StudentService::StudentService(std::vector<Student*> students) {
   // code
}

It won't be correct to just use the std::vector::operator= operator and write this->students = students , because that will only copy the pointer addresses and so if someone from the outside deletes the objects pointed to by those pointers, then the StudentService class would suffer as a result. 仅使用std::vector::operator=运算符并编写this->students = students是不正确的,因为这只会复制指针地址,因此如果外部某人删除了那些指向的对象指针,然后StudentService类将受到影响。

The solution is to loop through each pointer in the students parameter and create a new dynamic object, something like this: 解决方案是循环遍历students参数中的每个指针并创建一个新的动态对象,如下所示:

for(int i = 0; i < students.size(); i++) {
   this->students.at(i) = new Student(*students.at(i));
}

But even that is not proper due to the fact that it will create ONLY Student objects. 但即使这样也不合适,因为它会创建ONLY Student对象。 And we know that a Student can be a Freshman, Sophmore, Junior or Senior. 我们知道学生可以是新生,索菲尔,初中或高级。 So here is my question: what's the best solution to this problem? 所以这是我的问题:这个问题的最佳解决方案是什么?

I guess one way would be to place a private enum field inside each Student class and have 4 if-else statements checking what type of Student it is and then creating a new dynamic object based on that like so: 我想有一种方法是在每个Student类中放置一个私有枚举字段,并有4个if-else语句检查它是什么类型的Student,然后根据它创建一个新的动态对象:

 for(int i = 0; i < students.size(); i++) {
   if(students.at(i).getType() == FRESHMAN) {
      this->students.at(i) = new Freshman(*students.at(i));
   } else if(students.at(i).getType() == SOPHMORE) {
      this->students.at(i) = new Sophmore(*students.at(i));
   } else if {
   // and so on...
   }
}

But this still seems quite cumbersome, so what would you suggest? 但这仍然看起来很麻烦,你会建议什么?

You're looking for the Clone pattern. 你正在寻找克隆模式。 Add a clone() virtual function to Student, which is overridden in each descendant and creates the appropriate copy. 向Student添加clone()虚函数,在每个后代中重写并创建相应的副本。 Then write deep copy of containers as you've correctly specified. 然后按照您正确指定的方式编写容器的深层副本。

Edit: my work assumption is that your Freshman, etc. classes are descending from Student. 编辑:我的工作假设是你的新生等班级来自学生。 If not, use a variant<> and apply a copy visitor. 如果没有,请使用变体<>并应用副本访问者。

Resolving ownership issues 解决所有权问题

If you deem to shared the Student -s between your modules, then you are facing an ownership issue, and I would recommend using vector of std::shared_ptr<Student> -s to solve it. 如果您希望在模块之间共享Student ,那么您将面临所有权问题,我建议使用std::shared_ptr<Student> -s的向量来解决它。

If you have a std::vector<std::shared_ptr<Student>> , you can pass it to anyone you want. 如果你有一个std::vector<std::shared_ptr<Student>> ,你可以将它传递给任何你想要的人。 The receiver can copy the vector using an assignment operator and later on any objects he adds/removes won't affect the original container, just like you seem to desire. 接收器可以使用赋值运算符复制vector ,稍后他添加/删除的任何对象都不会影响原始容器,就像您希望的那样。

Resolving cloning issues 解决克隆问题

If you are interested in each module having its own copy of a Student -s vector, you are facing a cloning issue. 如果您对每个具有自己的Student -s向量副本的模块感兴趣,那么您将面临克隆问题。

You could resolve it by adding the following method to your classes: 您可以通过向您的类添加以下方法来解决它:

class Student {
    [..]
    virtual Student * clone() const = 0; // Assuming Student is abstract, otherwise implement as well
};

class Freshman : public Student {
    [..]
    virtual Freshman * clone() const { return new Freshman(*this); }
};

// Same for other derived classes...

And then using std::transform to copy the vector: 然后使用std::transform复制向量:

// students is the original std::vector<Student *>
std::vector<Student *> copy(students.size());
std::transform(students.begin(), students.end(), copy.begin(), [](Student * s) -> Student * { return s->clone(); });

BTW, it's Sophomore, not Sophmore... 顺便说一句,这是二年级学生,不是索菲尔......

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