MySQL ORDER BY第一列和第二列

Question

My question is different but I have read this similar SO post: How can I order by two columns, if result is equal, consider another column?

I am interested in 2 columns:

• production_id
• date

The query is:

SELECT BATCH_ISSUED.production_id, MANUFACTURE_DATE.date
FROM BATCH_ISSUED LEFT JOIN
     MANUFACTURE_DATE
     ON BATCH_ISSUED.production_id = MANUFACTURE_DATE.production_id
WHERE MANUFACTURE_DATE.active='1'
ORDER BY MANUFACTURE_DATE.date ASC,BATCH_ISSUED.production_id ASC

This fetches the data and sorts it by date (old > new) and then sorts by id but it needs to group all of the same id together which may mean GROUP BY needs to be included somehow.

An example of the data:

195 2017-10-10
196 2017-10-10
196 2017-10-10
258 2017-10-10
258 2017-10-10
189 2017-10-12
190 2017-10-12
258 2017-10-12
212 2017-10-13
213 2017-10-13

It should be presented like this, for example with the ID 258 kept together in date order:

    195 2017-10-10
    196 2017-10-10
    196 2017-10-10

    258 2017-10-10
    258 2017-10-10
    258 2017-10-12

    189 2017-10-12
    190 2017-10-12
    212 2017-10-13
    213 2017-10-13

Many thanks for any suggestions!

Answer 1

足以按顺序反转您的订单：

 ORDER BY BATCH_ISSUED.production_id DESC, MANUFACTURE_DATE.date ASC,

Answer 2

First, your WHERE clause turns the OUTER JOIN to an INNER JOIN . As a result, the JOIN is not even needed. So your query is equivalent to:

SELECT md.production_id, md.date
FROM MANUFACTURE_DATE md
WHERE md.active = 1
ORDER BY md.date ASC, md.production_id ASC;

Then you can use a JOIN to get the information you want:

SELECT md.production_id, md.date
FROM MANUFACTURE_DATE md JOIN
     (SELECT md2.production_id, MIN(md2.date) as mind
      FROM MANUFACTURE_DATE md2
      WHERE md.active = 1
      GROUP BY md2.production_id
     ) mmd
     ON md.production_id = md2.production_id
WHERE md.active = 1
ORDER BY mdd.mind ASC, md.production_id ASC, md.date;