mySQL 获取具有列最大值的行

Question

How can I fetch the full row that contain the max(column).
Example:
I have a table like this

+----+---------------+------+---------------------+
| id | title         | c    | update              |
+----+---------------+------+---------------------+
|  1 | John S.       |   15 | 2017-09-15 09:04:13 |
|  1 | John S.       |   21 | 2017-09-15 09:04:29 |
|  1 | John S.       |   22 | 2017-09-16 01:55:26 |
| 43 | Cristover Co. |   15 | 2017-09-17 14:11:43 |
| 43 | PeterSberg R. |   16 | 2017-09-17 15:12:30 |
| 43 | Cristover Co. |   19 | 2017-09-17 21:45:10 |
+----+---------------+------+---------------------+

Now I want to select the row that contains the max(update). Expected result:

+----+---------------+------+---------------------+
| id | title         | c    | update              |
+----+---------------+------+---------------------+
| 43 | Cristover Co. |   19 | 2017-09-17 21:45:10 |
+----+---------------+------+---------------------+

Answer 1

try this one

SELECT * FROM table_name 
    WHERE table_name.update = 
    (SELECT max(table_name.update) from table_name)

Answer 2

First, you shouldn't name your column update , choose another name, let's say "date_of_update"

If you want to select only the row with the most recent update, you can simply use something like this :

SELECT * FROM table_name ORDER BY date_of_update DESC LIMIT 1.

This will give you only one row with the max date!