如何使用 Gulp 对 uglify js 进行 gzip 压缩而不在 dist 文件夹中生成两个文件

Question

I'm new using Gulp.

I'm wondering how can I concat, uglify and gzip all the js files from a static website using Gulp.

I have a task like this that works but I would like to only include in the dist folder the .gz file and not the combined.js

gulp.task("concat-js", function () {
return gulp.src("./src/js/*.js")
    .pipe(concat("combined.min.js"))
    .pipe(uglify())
    .pipe(gzip())
    .pipe(gulp.dest("./build/js"));
});

UPDATE

I encourage you to read the comments. In my case, the problem has been caused by a bad use of gulp-useref, because was generating the file at the end of the build process. Probably noob problem, but hopefully can help anyone.

Thanks in advance...

Answer 1

This should work. Just store the .min file in a temp folder. You can delete that later if you want.

gulp.task("concat-js", function () {
  return gulp.src("./src/js/*.js")
   .pipe(concat("combined.min.js"))

   .pipe(gulp.dest('./temp'))

   .pipe(uglify())
   .pipe(gzip())
   .pipe(gulp.dest("./build/js"));
});

The final file would be "combined.min.js.gz" the only one in build/js. If you don't like that name you could rename it with gulp-rename .