[英]#Sql Comparing data of one table to that of select query result
I have table 1 with A,B,C,D,E column and the result of select query after combining the table 2 and table 3 is A, D column(few values as compare to table 1) Say view 1. 我有带有A,B,C,D,E列的表1,将表2和表3合并后的选择查询结果是A,D列(与表1相比,值很少)说视图1。
Now I need to run another query if value of column A,D of table 1 is in resulted view. 现在,如果在结果视图中表1的A,D列的值,我需要运行另一个查询。 this new query also have where conditions and combining two tables 这个新查询还具有条件条件并结合了两个表
Could anyone please let me know the best way out? 有人可以让我知道最好的出路吗?
Example Table1 示例表1
A B C D
Fruit Orange 1 3
Vegetable Onion 89 3
Fruit Mango 83 22
Fruit Banana 3 2
Vegetable Beans 382 2
View1 查看1
A B
Fruit Orange
Fruit Banana
Vegetable Beans
Final output 最终输出
A B C D
Fruit Orange 1 3
Fruit Banana 3 2
Vegetable Beans 382 2
SELECT
view1.a,
view1.b,
table1.c,
table1.d
FROM
table1
JOIN (
--select query of your view
SELECT
*
FROM
your_view
) view1 ON
table1.a = view1.a
AND
table1.b = view1.b;
All you need is the inner join
between your table and view. 您所需要做的就是表和视图之间的inner join
。 Inner join
will find the matches of column A & B
in both tables. Inner join
将在两个表中找到列A & B
的匹配项。
select table1.*
from table 1
inner join view1
on table1.a = view1.a
and table1.b = view1.b;
Hope it helps! 希望能帮助到你!
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