如何在python中将一个包含5个元素的集合变成5个集合，每个集合一个元素？

Question

Lets say I have 2 sets of lists.

set1 = [2, 4, 6, 8, 10]
set2 = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

From here I've tried to subtract set1 from set2 in order to get [1, 3, 5, 7, 9] , and I've done so by saying print [x for x in set2 if x not in set1] The output is just set2 , because there is only one element in set 2, and that is the list of all natural numbers up to and including 10.

So my question is how do I turn [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] into [[1],[2],[3],[4],[5],[6],[7],[8],[9],[10]] ?

I know this is a basic question, but I'm new and I couldn't find any other questions like this. Please answer with answers that help in general and not only in this situation. Thanks in advance.

Answer 1

You can try this:

s = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
new_s = [[i] for i in s]

Output:

[[1], [2], [3], [4], [5], [6], [7], [8], [9], [10]]

Answer 2

you can use sets to solve the stated problem

set1 = [2, 4, 6, 8, 10]
set2 = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

set(set2) - set(set1)

Out[18]: {1, 3, 5, 7, 9}  

the list comprehension works too, did you have a different result?

[e for e in set2 if e not in set1]

Out[17]: [1, 3, 5, 7, 9]