[英]Access Query Find All records Where all Linked Records Match
Tables: 表格:
tblStudents:
ID, Student Name
1, John
2, Mark
3, Fred
tblEnrolledSubjects:
ID, Student ID, Subject ID, Score
1, 1, 1, 75
2, 1, 2, 75
3, 1, 3, 75
4, 1, 4, NULL
5, 2, 1, 75
6, 3, 1, 75
7, 3, 2, 80
8, 3, 3, 85
tblSubject:
ID, Subject Name
1, Maths
2, English
3, Science
4, History
I want to return all distinct students that have a score of over (say 70) for all subjects. 我想返回所有学科得分都超过(例如70分)的不同学生。 SELECT [Student Name]
选择[学生姓名]
Students can be enrolled in 1 or more subjects. 学生可以注册1个或多个科目。 If a student has even one subject not of required score then they should not be listed.
如果学生甚至有一门学科没有达到要求的分数,则不应列出他们。
From he above data I would expect to see 从他上面的数据我希望看到
Mark
Fred
What would the SQL query be for this? SQL查询将对此做什么?
If a NULL
value doesn't count against you, then 如果
NULL
值对您不利,那么
SELECT tblStudents.[Student Name]
FROM tblEnrolledSubjects RIGHT JOIN tblStudents
ON tblEnrolledSubjects.[Subject ID] = tblStudents.ID
GROUP BY tblStudents.[Student Name]
HAVING (Min(tblEnrolledSubjects.[Score])>=70);
SELECT t.Studentname
FROM tblStudents t JOIN
(select count(*) cnt, min(nz(score,0)) minscore, StudentID
FROM tblEnrolledSubjects
GROUP BY StudentID) s
ON t.Studentid = s.studentid
WHERE minscore>=70 --if mark is greater than or equal to 70
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