使用 rsync 在脚本上无限循环

Question

I made a function using rsync copying file from rep1 to rep2. I used getopt to create an argument calling this function. The function is called in the case but doing an infinite loop, i don't know why. I tried this function without case and it worked nicely.

Stuff in rsync():

    read -p 'Enter source directory : ' repSource
    read -p 'Enter destination directory : ' repDest


    if [ -e $repSource ] && [ -d $repSource ] && [ -e $repDest ] && [ -d $repDest ]
    then
            echo "File exists and it is a directory !"
            echo "Synchronisation of " $repSource "to " $repDest
            rsync -av $repSource  $repDest


    else

            echo "File doesn't exit or it is not a directory  !"
    fi

Here my case:

OPTS=$(getopt -o h,m,p,a,l,t) 
if [ $? != 0 ]
then
    exit 1
fi

    case "$1" in

             -h) aide;
               exit 0;;
             -m) RAM;
               exit 0;;
             -p) CPU;
               exit 0;;
             -a) logcpu;
               exit 0;;
             -l) autolog;
               exit 0;;
             -t) rsync;
               exit 0;;
    esac

Here the result:

Enter source directory : rep1/
Enter destination directory : rep2/
File exists and it is a directory !
Synchronisation of  rep1/ to  rep2/
Enter source directory :

Thanks for your help!

Answer 1

You are shadowing the "real" command rsync with your function of the same name. You can keep rsync as the function name, but then you need to use the built-in command to ignore the function and call the real command.

command rsync -av "$repSource" "$repDest"