json文件Javascript的正确格式是什么？
[英]What is the correct format for json file Javascript?
问题描述
I am trying to test a simple code where I am extracting data from JSON file and displaying an alert. 
我正在尝试测试一个简单的代码，该代码用于从JSON文件提取数据并显示警报。 I am confused about the format of the JSON file. 我对JSON文件的格式感到困惑。 The following code works perfectly fine: Working code 以下代码可以正常工作 ： 工作代码 Code:
码：
<!DOCTYPE html>
<html>
<body>
<h2>My First Web Pags</h2>
<p>My first paragraph.</p>
<script>
var text = '{ "name":"John", "birth":"1986-12-14", "city":"New York"}';
var jsonScript = JSON.parse(text);
var titledata = jsonScript.name;
alert(titledata);
</script>
</body>
</html>
On the other hand, when I change the format of the JSON, the alert is not generated. 另一方面，当我更改JSON的格式时，不会生成警报。 Faulty Code 错误的代码 Code:
码：
<!DOCTYPE html>
<html>
<body>
<h2>My First Web Pags</h2>
<p>My first paragraph.</p>
<script>
var text = '{ "name":"John", "birth":"1986-12-14", "city":"New York"
}';
var jsonScript = JSON.parse(text);
var titledata = jsonScript.name;
alert(titledata);
</script>
</body>
</html>
I am trying to write a php script that uses a Stock symbol (ex. AAPL for Apple and MSFT for Microsoft) to request a XML file containing stock news about the searched company. 我正在尝试编写一个使用Stock符号的php脚本（例如，Apple的AAPL和Microsoft的MSFT）来请求一个XML文件，其中包含有关被搜索公司的股票新闻。 All the stock news come from the Seeking Alpha Stock News RSS feed. 所有股票新闻均来自Seeking Alpha股票新闻RSS feed。 The response is a XML-Formatted object. 响应是XML格式的对象。 The php script should parse the returned XML-formatted object, extract the necessary fields and build a JSON object to be sent to the client. php脚本应解析返回的XML格式的对象，提取必要的字段并构建一个JSON对象以发送给客户端。 I am using the following php code for that: 我为此使用以下php代码：
$note = "https://seekingalpha.com/api/sa/combined/".$symbol.".xml";
$xml=simplexml_load_file($note) or die("Error: Cannot create object");
$jsonNews = json_encode($xml);
The returned json data seems to have some problem with the formatting. 返回的json数据似乎在格式化方面存在问题。 I have created a sample json data which is of the same format as the json returned by php script. 我创建了一个示例json数据，其格式与php脚本返回的json格式相同。 If the format is incorrect, how do i correct the format? 如果格式不正确，如何纠正格式？
2 个解决方案
解决方案1
0 2017-10-16 22:20:13
It is not the format of the json: 它不是json的格式：
"aaa
bbb"
is not a valid string (see the coloring of the code (Edit: I mean in the image)) 不是有效的字符串（请参见代码的颜色（编辑：我的意思是图像中的内容））
You could do 你可以做
"aaa"+
"bbb"
(same as "aaabbb") or （与“ aaabbb”相同）或
"aaa\nbbb"
if you wish to include a newline in the string 如果您希望在字符串中包含换行符
Edit: So in your case: 编辑：因此在您的情况下：
'{"name": "John","birth": "1986-12-14","city": "new York"
}' - not a valid json string because not a valid string
'{"name": "John","birth": "1986-12-14","city": "new York"'+
'}' - a valid json string
'{"name": "John","birth": "1986-12-14","city": "new York"\n}' - a valid json string with a newline
解决方案2
0 2017-10-16 22:27:26
You don't need define JSON objects from strings, that is causing you an error typing incorrectly the last '}' symbol out of your string var. 您不需要从字符串定义JSON对象，这会导致您错误输入字符串var中最后一个'}'符号。 You should place write there: +'}'; 您应该在此处写：+'}';
Nevertheless JSON is the Javascript Object Notation, so you can use it as an object definition: 不过，JSON是Javascript Object Notation，因此您可以将其用作对象定义：
var jsonScript = {
name: "Jhon",
birth: "1986-12-14",
city: "New York"
}
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