如何在文件名后添加注释自动保存？

Question

I am extracting data from files and I'd like to apply these working (ugly) command lines to all the txt files from a given folder. Thus I would also need to append a string to the output file name to avoid overwriting during the loop... any suggestion is warmly welcome.

for file in ./TEST/;
    do 
        awk '/R.Time/,/LC/' 070_WT3a.txt|awk '/R.Time/,/PDA/'|grep -v -E "PDA|LC"|grep -w -v "80,00000"|grep -w -v "80,00833"|grep -w -v "80,01667"|grep -w -v "80,01067"|grep -w -v "80,02133"|sed -n '1,9601p' > ./Output/Fluo.txt;
        awk '/R.Time/,/LC/' 070_WT3a.txt|awk '/R.Time/,/PDA/'|grep -v -E "PDA|LC"|grep -w -v "80,00000"|grep -w -v "80,00833"|grep -w -v "80,01667"|grep -w -v "80,01067"|grep -w -v "80,02133"|sed -n '9603,19203p' > ./Output/RID.txt;
    done

Answer 1

Inside the loop you can use the variable ${file} . A first improvement (with additional lines that you can add after a pipe) :

for file in ./TEST/;
do 
   filebasename=${file##*/}
   awk '/R.Time/,/LC/' ${file}.txt |
      awk '/R.Time/,/PDA/' |
      grep -v -E "PDA|LC" |
      grep -w -v "80,00000"|
      grep -w -v "80,00833"|
      grep -w -v "80,01667"|
      grep -w -v "80,01067"|
      grep -w -v "80,02133"|
      sed -n '1,9601p' > ./Output/Fluo_${filebasename};
   awk '/R.Time/,/LC/' 070_WT3a.txt |
      awk '/R.Time/,/PDA/'|
      grep -v -E "PDA|LC"|
      grep -w -v "80,00000"|
      grep -w -v "80,00833"|
      grep -w -v "80,01667"|
      grep -w -v "80,01067"|
      grep -w -v "80,02133"|
      sed -n '9603,19203p' > ./Output/RID_${filebasename};
done

The next thing you can do is improving the parsing.
Without example input/output it is hard to see/test a solution, I can not tell for sure that all files needs to be split on lines 9601/9603/19203, what seems to be working for 070_WT3a.txt. I would like to start with skipping the 80* lines, but these lines might have the boundaries R.Time/LC inside, so that won't help. You might want to test on 070_WT3a.txt with

awk '/R.Time/,/LC/' 070_WT3a.txt |awk '/R.Time/,/PDA/'|
   grep -v -E "PDA|LC"|grep -Ewv "80,0(0000|0833|1667|1067|2133)"

You can try to combine the 2 awk 's into one (or even get the grep 's inside the awk , but that is becoming offtopic and difficult to test without clear requirements and examples.

EDIT: After testing with an example input I found this simplified:

for file in TEST/*.txt; do 
   filebasename=${file##*/}
   awk '/LC Chromatogram(Detector A-Ch1)/,/^80,/' "${file}" | 
      grep -E "^[0-7]" > Output/Fluo_${filebasename}
   awk '/LC Chromatogram(Detector B-Ch1)/,/^80,/' "${file}" |
      grep -E "^[0-7]" > Output/RID_${filebasename}
done

Inside the loop I use ${file}, that will have different filenames each loop. The filenaam is also used for the name of the outputfiles. The filename will start with TEST/ , that can be stripped with ${file##*/} (there are a lot different ways like using cut -d"/" and sed 's/.. , this one is fast).