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Groovy:解析xml

[英]Groovy:Parse xml

I want to parse xml by groovy XmlSlurper my current xml schema looks like this and i want to get data value of each tag ( i mean value of start,startDate and endDate) , have code like this 我想通过groovy XmlSlurper解析xml,我当前的xml模式看起来像这样,我想获取每个标签的数据值(我的意思是start,startDate和endDate的值),具有这样的代码

def root = new XmlSlurper().parseText(content);
        for (item in root.item){
            start=item.start;
        }

but it doesn't work what should i change?: 但它不起作用我应该更改什么?:

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<serviceList>    
<ms>        
<CrossCycle>            
<details>                
<start>2017-09-07</start>                
<startDate>2017-02-02</startDate>                
<endDate>2017-03-02</endDate>                            
 </details>        
 </CrossCycle>    
 </ms>
 </serviceList>

Just do: 做就是了:

def listOfMaps = root.ms.CrossCycle.details.collect { node -> [ 
    start: node.start.text(),
    startDate: node.startDate.text(),
    endDate: node.endDate.text()
  ]
}

Then listOfMaps is a list with a map for each CrossCycle.details block 然后listOfMaps是一个列表,其中包含每个CrossCycle.details块的映射

ie: 即:

assert listOfMaps[0].start == '2017-09-07'

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