[英]regexp_substr: find the text before a given patern
I want to find the text before a given pattern. 我想在给定模式之前找到文本。 My main problem is when my text has many rows. 我的主要问题是我的文本有很多行。
Here the example: 这里的例子:
SQL> with foo as
2 (select '1 first test error log blabla ' k from dual
3 union
4 select '2 second test
5 zz error log blablabla ' k from dual
6 )
7 SELECT REGEXP_SUBSTR(k,'.*error log',1,1) AS result_
8 ,k from foo;
RESULT_ K
------------------------------------- -------------------------------------
1 first test error log 1 first test error log blabla
zz error log 2 second test
zz error log blablabla
The result is false for the second rows. 第二行的结果为false。 It should be: 它应该是:
RESULT_ K
------------------------------------- -------------------------------------
1 first test error log 1 first test error log blabla
2 second test 2 second test
zz error log zz error log blablabla
I run this query on a 11.2 Oracle database 我在11.2 Oracle数据库上运行此查询
From the Oracle documentation , the 5th argument to REGEXP_SUBSTR
is: 从Oracle文档中 , REGEXP_SUBSTR
的第五个参数是:
match_parameter
is a text literal that lets you change the default matching behavior of the function.match_parameter
是文本文字,可让您更改函数的默认匹配行为。
Which has the options : 可以选择 :
'n'
allows the period (.
), which is the match-any-character character, to match the newline character.'n'
允许句点(.
)(它是任何字符的匹配字符)与换行符匹配。 If you omit this parameter, then the period does not match the newline character. 如果省略此参数,则句点与换行符不匹配。
Oracle 11g R2 Schema Setup : Oracle 11g R2架构设置 :
CREATE TABLE table_name ( k ) AS
SELECT '1 first test error log blabla ' FROM DUAL UNION ALL
SELECT '2 second test
zz error log blablabla ' FROM DUAL;
Query 1 : 查询1 :
SELECT REGEXP_SUBSTR(k,'.*error log',1,1,'n') AS result_,
k
FROM table_name
| RESULT_ | K |
|------------------------|--------------------------------|
| 1 first test error log | 1 first test error log blabla |
| 2 second test | 2 second test |
| zz error log | zz error log blablabla |
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.