正则表达式匹配％，但不匹配\\％

Question

I'm struggling to find the right regex for the case where I want to match a '%' but only if it's not preceded by a '\\' between quotations.

For example I want this to come back as a match

Test \\" this % matches \\" test

But not match

Test \\" this \\% doesn't match \\" test

Would a regex master be willing to assist me with this?!

Ultimately my goal is to ensure every '%' is escaped when found within quotations.

Edit: Here's what I have right now

This is currently what I have but definitely isn't correct.

\\". [%][^\\%]. \\"

Answer 1

([^\\]|\\[^%])*

It looks like this seems to work in my tests on https://regex101.com/

The sections are ( [^\\\\] | \\\\[^%] )*

The ()* means 0 or more of the contained group.

The contained group is either [^\\\\] or \\\\[^%] . The first case is "any character that is not a backslash," which include the percent sign. The second case is "a backslash followed by any character that is not a percent sign."

The [^ ] operator is "any character except these."